ANSWER: The guidelines your see such as the you to you estimate use simply in the event the costs is looked at as an ongoing fluid that will spread itself on people epidermis, it doesn’t matter how highest, and get zero thickness. Needless to say, an instance like you define, having 5 a lot of electrons is during no chance such as for instance a fluid and that i manage reckon that sets from 5-0 to 0-5 will be the shipping more a period. Theoretically, the five electrons perform strategy themselves in order for for every was since far away about almost every other cuatro that one can, but around would not be a new like shipping.
QUESTION: Is it you can so you’re able to suspend a keen electron via electrostatic levitation within the a good consistent magnetic industry? Incase the brand new current is decreased enough so the electrostatic push toward electron is actually below the fresh new force on account of the electron’s weight do brand new electron following experience a great ‘fall’ owed so you’re able to gravity?
I’m asking this simply because I am questioning if the establishing a great positron from inside the an effective uniform magnetized job (inside the a vacuum) and you may reducing the voltage to help you a highly quick really worth so as that the electrostatic force is gloomier than the pounds carry out trigger a positron to in addition to experience an effective ‘fall’. Of course, if it did experience an autumn it may be determined whether or not it perform fall up otherwise downwards.
By inertial bulk What i’m saying is the proportion of your own push your affect they split by the White Sites dating site speed, simply put their resistance to getting accelerated
I’m 17 years of age plus the uk going to studies physics on school when you look at the sep and you may was just curious about this because a subjects in 2010 try electricity phenomena and you may we chatted about millikan’s petroleum drop try and therefore appeared an equivalent form of suspension in the event that electrostatic force and force due to gravity were healthy.
Now, we know so you’re able to extraordinary reliability that inertial size from an effective positron is equivalent to the new inertial mass regarding an electron
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.